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X^2-2X+7/10=0
We multiply all the terms by the denominator
X^2*10-2X*10+7=0
Wy multiply elements
10X^2-20X+7=0
a = 10; b = -20; c = +7;
Δ = b2-4ac
Δ = -202-4·10·7
Δ = 120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{120}=\sqrt{4*30}=\sqrt{4}*\sqrt{30}=2\sqrt{30}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-2\sqrt{30}}{2*10}=\frac{20-2\sqrt{30}}{20} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+2\sqrt{30}}{2*10}=\frac{20+2\sqrt{30}}{20} $
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